Two-Step Equations: Steps and Examples

A two-step equation needs two inverse operations to solve, like $3x + 5 = 20$ . To solve two-step equations, first undo the adding or subtracting, then undo the multiplying or dividing. Do each step to both sides: $3x + 5 = 20$ becomes $3x = 15$ , so $x = 5$ .

Before this lesson: You should know how to solve one-step equations and how to use the order of operations.

Extra practice: The Algebra 1 Unit 2 Practice Pack has printable problems, answer keys and a cheat sheet for this unit.

What Is a Two-Step Equation?

In a two-step equation, two things are done to the variable. In $3x + 5 = 20$ , the variable is multiplied by 3, and then 5 is added.

To solve it, undo those steps in reverse order. Think about getting dressed: you put on socks, then shoes. To undress, you take off the shoes first, then the socks.

Top row: start with x, multiply by 3 to get 3x, then add 5 to get 3x + 5 = 20. Bottom row: start with 20, subtract 5 to get 15, then divide by 3 to get x = 5. — Build the expression in one order, then undo it in the reverse order.

The last thing done to the variable was adding 5, so subtract 5 first. Then divide by 3.

How to Solve Two-Step Equations

Undo the adding or subtracting. Do it to both sides.
Undo the multiplying or dividing. Do it to both sides.
Check your answer in the original equation.

\begin{aligned} 3x + 5 &= 20 \\ 3x + 5 - 5 &= 20 - 5 \\ 3x &= 15 \\ \frac{3x}{3} &= \frac{15}{3} \\ x &= 5 \end{aligned}

Check: $3(5) + 5 = 15 + 5 = 20$ . It works.

Worked Examples

Example 1: Negative numbers

Solve $-2y - 7 = 9$ .

-2y - 7 + 7 = 9 + 7

Step 1. 7 is subtracted, so add 7 to both sides.

-2y = 16

Step 2. Simplify each side.

\frac{-2y}{-2} = \frac{16}{-2}

Step 3. The variable is multiplied by $-2$ , so divide both sides by $-2$ (see one-step equations).

y = -8

Step 4. Simplify. A positive divided by a negative is negative. (See multiplying and dividing integers.)

Answer: $y = -8$

Check: $-2(-8) - 7 = 16 - 7 = 9$ . It works.

Example 2: Division

Solve $\frac{x}{4} - 3 = 2$ .

\frac{x}{4} - 3 + 3 = 2 + 3

Step 1. Add 3 to both sides.

\frac{x}{4} = 5

Step 2. Simplify each side.

4 \cdot \frac{x}{4} = 4 \cdot 5

Step 3. The variable is divided by 4, so multiply both sides by 4.

x = 20

Step 4. Simplify.

Answer: $x = 20$

Check: $\frac{20}{4} - 3 = 5 - 3 = 2$ . It works.

Example 3: Variable on the right side

Solve $11 = 5 - 3k$ .

11 - 5 = 5 - 3k - 5

Step 1. The variable can be on either side. 5 is added to the variable term, so subtract 5 from both sides.

6 = -3k

Step 2. Simplify each side.

\frac{6}{-3} = \frac{-3k}{-3}

Step 3. Divide both sides by $-3$ .

-2 = k

Step 4. Simplify.

k = -2

Step 5. Write the variable first.

Answer: $k = -2$

Check: $5 - 3(-2) = 5 + 6 = 11$ . It works.

Example 4: A fraction coefficient

Solve $\frac{2}{3}m + 4 = 10$ .

\frac{2}{3}m + 4 - 4 = 10 - 4

Step 1. Subtract 4 from both sides.

\frac{2}{3}m = 6

Step 2. Simplify each side.

\frac{3}{2} \cdot \frac{2}{3}m = \frac{3}{2} \cdot 6

Step 3. Multiply both sides by the reciprocal of $\frac{2}{3}$ , which is $\frac{3}{2}$ . (See multiplying and dividing fractions.)

m = \frac{3}{2} \cdot 6

Step 4. Simplify the left side. $\frac{3}{2} \cdot \frac{2}{3} = 1$ .

m = 9

Step 5. Multiply on the right. $\frac{3}{2} \cdot 6 = \frac{18}{2} = 9$ .

Answer: $m = 9$

Check: $\frac{2}{3}(9) + 4 = 6 + 4 = 10$ . It works.

Example 5: Word problem

A gym charges $35 to join, plus $15 each month. Jordan has paid $125 in total. How many months has Jordan been a member?

15m + 35 = 125

Step 1. Let $m$ = the number of months. The cost is $15m + 35$ , and it equals 125.

15m + 35 - 35 = 125 - 35

Step 2. Subtract 35 from both sides.

15m = 90

Step 3. Simplify each side.

\frac{15m}{15} = \frac{90}{15}

Step 4. Divide both sides by 15.

m = 6

Step 5. Simplify.

Answer: Jordan has been a member for 6 months.

Check: $15(6) + 35 = 90 + 35 = 125$ . It works.

Common Mistakes

Mistake	What it looks like	How to fix it
Dividing only one term	$3x + 5 = 20$ becomes $x + 5 = \frac{20}{3}$	Undo the adding first: subtract 5, then divide by 3.
Subtracting when you should add	$-2y - 7 = 9$ becomes $-2y = 2$	Undo subtracting 7 by adding 7: $-2y = 16$ .
Dropping the negative sign	$-2y = 16$ , so $y = 8$	Divide by $-2$ : $y = -8$ .
Mixing up the fraction bar	$\frac{x + 3}{4} = 5$ , so $x + 3 = 5 - 4$	The 4 divides the whole top. Multiply by 4 first: $x + 3 = 20$ .
Skipping the check	Writing an answer and moving on	Substitute your answer. If the two sides aren’t equal, look for a sign error.

When a Fraction Bar Covers a Whole Side

The fraction bar acts like parentheses. It changes which step comes first. Compare these two equations:

\begin{aligned} \frac{x}{3} + 4 &= 6 & &\Rightarrow & \frac{x}{3} &= 2 & &\Rightarrow & x &= 6 \\ \frac{x + 4}{3} &= 6 & &\Rightarrow & x + 4 &= 18 & &\Rightarrow & x &= 14 \end{aligned}

In the first one, only $x$ is divided by 3, so subtract 4 first. In the second one, all of $x + 4$ is divided by 3, so multiply by 3 first. Equations with parentheses or more terms are covered in multi-step equations.

Practice Problems

Solve each equation. Check your answer.

$2x + 3 = 11$
$5a - 4 = 21$
$-3m + 8 = -7$
$\frac{n}{6} + 2 = 9$
$7 - 4p = 27$
$\frac{w}{-2} - 5 = 1$
$0.5x + 1.5 = 4$
$\frac{3}{5}y - 4 = 8$
$\frac{x + 3}{4} = 5$
A phone repair shop charges a $40 fee plus $25 for each hour of work. A repair costs $115. How many hours did it take?

Answers

Show answers

2x + 3 - 3 = 11 - 3

Subtract 3 from both sides.

2x = 8

Simplify.

\frac{2x}{2} = \frac{8}{2}

Divide both sides by 2.

x = 4

Simplify.

Check: $2(4) + 3 = 8 + 3 = 11$

5a - 4 + 4 = 21 + 4

Add 4 to both sides.

5a = 25

Simplify.

\frac{5a}{5} = \frac{25}{5}

Divide both sides by 5.

a = 5

Simplify.

Check: $5(5) - 4 = 25 - 4 = 21$

-3m + 8 - 8 = -7 - 8

Subtract 8 from both sides.

-3m = -15

Simplify.

\frac{-3m}{-3} = \frac{-15}{-3}

Divide both sides by −3.

m = 5

Simplify.

Check: $-3(5) + 8 = -15 + 8 = -7$

\frac{n}{6} + 2 - 2 = 9 - 2

Subtract 2 from both sides.

\frac{n}{6} = 7

Simplify.

6 \cdot \frac{n}{6} = 6 \cdot 7

Multiply both sides by 6.

n = 42

Simplify.

Check: $\frac{42}{6} + 2 = 7 + 2 = 9$

7 - 4p - 7 = 27 - 7

Subtract 7 from both sides.

-4p = 20

Simplify.

\frac{-4p}{-4} = \frac{20}{-4}

Divide both sides by −4.

p = -5

Simplify.

Check: $7 - 4(-5) = 7 + 20 = 27$

\frac{w}{-2} - 5 + 5 = 1 + 5

Add 5 to both sides.

\frac{w}{-2} = 6

Simplify.

-2 \cdot \frac{w}{-2} = -2 \cdot 6

Multiply both sides by −2.

w = -12

Simplify.

Check: $\frac{-12}{-2} - 5 = 6 - 5 = 1$

0.5x + 1.5 - 1.5 = 4 - 1.5

Subtract 1.5 from both sides.

0.5x = 2.5

Simplify.

\frac{0.5x}{0.5} = \frac{2.5}{0.5}

Divide both sides by 0.5 (see operations with decimals)

x = 5

Simplify.

Check: $0.5(5) + 1.5 = 2.5 + 1.5 = 4$

\frac{3}{5}y - 4 + 4 = 8 + 4

Add 4 to both sides.

\frac{3}{5}y = 12

Simplify.

\frac{5}{3} \cdot \frac{3}{5}y = \frac{5}{3} \cdot 12

Multiply both sides by the reciprocal, 5/3.

y = \frac{5}{3} \cdot 12

Simplify the left side.

y = 20

Multiply.

Check: $\frac{3}{5}(20) - 4 = 12 - 4 = 8$

4 \cdot \frac{x + 3}{4} = 4 \cdot 5

The whole top is divided by 4, so multiply both sides by 4 first.

x + 3 = 20

Simplify.

x + 3 - 3 = 20 - 3

Subtract 3 from both sides.

x = 17

Simplify.

Check: $\frac{17 + 3}{4} = \frac{20}{4} = 5$

10.

25h + 40 = 115

Let $h$ = the number of hours. The cost is $25 an hour plus the $40 fee.

25h + 40 - 40 = 115 - 40

Subtract 40 from both sides.

25h = 75

Simplify.

\frac{25h}{25} = \frac{75}{25}

Divide both sides by 25.

h = 3

Simplify.

Check: $25(3) + 40 = 75 + 40 = 115$
The repair took 3 hours.

Want more practice? The Algebra 1 Unit 2 Practice Pack has 51 pages of problems on this and the other lessons in the unit, with step-by-step answers and a cheat sheet.

Two-Step Equations FAQ

What is a two-step equation?

It is an equation that takes two inverse operations to solve, such as $4x - 1 = 11$ .

How do you solve two-step equations?

First add or subtract to get the variable term alone. Then multiply or divide to get the variable alone. Do each step to both sides.

Which step do you do first?

Usually you undo the adding or subtracting first, because that was the last thing done to the variable. The exception is when a fraction bar or parentheses group the whole side.

What if the variable is on both sides?

Then it takes more than two steps. First move the variable terms to one side, then solve. Learn how in equations with variables on both sides.

Summary

A two-step equation needs two inverse operations.
Undo the operations in reverse order: adding or subtracting first, then multiplying or dividing.
Do every step to both sides of the equation.
Watch negative signs when you divide.
Check your answer in the original equation.

Previous lesson: One-Step Equations

Next lesson: Multi-Step Equations

Back to the Algebra 1 Index